By Mohamed Khalgui
"This publication brings jointly theoretical and technical options of clever embedded keep watch over structures and their use in and software program architectures through highlighting formal modeling, execution versions, and optimum implementations"--Provided via publisher.
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Additional resources for Embedded computing systems : applications, optimization, and advanced design
Thus, if there are three charging tanks with one distiller, we can schedule the system such that fds is slightly less than fpmax and the amount of oil in the charging tanks can fill two tanks to capacity. When it switches to process from one type of oil to another, it needs to process a small amount of oil that is less than α, the total volume of crude oil in the charging tanks is reduced. However, because fpmax > fds, two tanks will be full again after some time. In this way, the system remains always in a safe state and the production rate is near the maximal one.
The answer is negative as shown in the following theorem.
Initially, at time τ0, M0(p1c) = 1 and V(M0(p1c, φ1)) = 3α, and all other places are empty. At this time, transition t12 fires to feed p1 and meanwhile y fires with color φ1 to charge p2s with volume ζ0. At time τ1 = τ0 + ζ0/fpmax, M1 is reached such that M1(p1c) = M1(p2s) = 1, V(M1(p1c, φ1)) = 3α - ζ0 > 2α, and V(M1(p2s, φ1)) = ζ0. At M1, t12 continues firing to feed p1, the firing of y switches to charge p3s with color φ2, and t21 fires. At τ2 = τ1 + 2Ψ, M2 is reached such that M2(p1c) = M2(p2c) = M2(p3s) = 1, V(M2(p1c, φ1)) = α - ζ0 > 0, V(M2(p2c, φ1)) = ζ0, and V(M2(p3s, φ2)) = 2α.