Information Security and Privacy: 16th Australasian by Claude Carlet (auth.), Udaya Parampalli, Philip Hawkes

By Claude Carlet (auth.), Udaya Parampalli, Philip Hawkes (eds.)

This e-book constitutes the refereed complaints of the sixteenth Australasian convention on info defense and privateness, ACISP 2011, held in Melbourne, Australia, in July 2011.
The 24 revised complete papers provided including an invited speak and nine poster papers have been rigorously reviewed and chosen from 103 submissions. The papers are equipped in topical sections on symmetric key cryptography, hash services, cryptographic protocols, entry keep watch over and safeguard, and public key cryptography.

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584–601. Springer, Heidelberg (2006) 5. : An infinite class of balanced functions with optimal algebraic immunity, good immunity to fast algebraic attacks and good nonlinearity. In: Pieprzyk, J. ) ASIACRYPT 2008. LNCS, vol. 5350, pp. 425–440. Springer, Heidelberg (2008) 6. : Covering codes. North-Holland, Amsterdam (1997) 7. : Algebraic attacks on stream ciphers with linear feedback. In: Biham, E. ) EUROCRYPT 2003. LNCS, vol. 2656, pp. 345–359. Springer, Heidelberg (2003) 46 M. Liu, D. Lin, and D.

Theorem 4. Let f ∈ Bn . If nlr (f ) = min{d(g, f ) | 1 ≤ deg(g) ≤ r}, then dair (f ) ≤ 12 nlr (f ). Proof. Since d(g, f ) = wt((g + 1)f ) + wt(g(f + 1)), we have dair (f ) = min{wt(gf ), wt(g(f + 1)) | 1 ≤ deg(g) ≤ r} = min{wt((g + 1)f ), wt(g(f + 1)) | 1 ≤ deg(g) ≤ r} d(g, f ) | 1 ≤ deg(g) ≤ r} 2 nlr (f ) = . 2 ≤ min{ Note that for a balanced function it always holds that nlr (f ) = min{d(g, f ) | 1 ≤ deg(g) ≤ r}. Therefore the result of [22] is a special case of Theorem 4. It is well known that any Boolean function h with AI > r has Hamming weight r r n n n i=0 i ≤ wt(h) ≤ 2 − i=0 i [10].

So there are 2n+223−72 = 2n+151 pairs remaining. Key Recovery. In the key recovery procedure, we use Property 2 and the precomputation table H to discard the wrong keys. 1. , 8, guess kla and keep the pairs that satisfy the equation Sl1 = (P −1 ( R0 ))l . Next guess k2a , so (L1 , L 1 ) can be computed. For each of the remaining pairs, do Step 2. 2. Initialize a table Γ of 2144 all possible values (k b , k2c , k e , k2d ), for each of the remaining pairs, access the row (L1 , ΔL12 , ΔR1 , R21 ) and the row (L10 , ΔL10 2 , ) in table H.

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